Question

Cisplatin or Platinol has a chemical PtCl2(NH3)2 that is used in the treatment of certain cancers. Calculate (a) the amount (mol) of compound in 285.3 g of cisplatin

Answer 1

Molar mass of cisplatin $[Pt(NH_3)_2Cl_2]=301.1 \frac{g}{mol}$

mass of cisplatin is given as 285.3 g

Mole of cisplatin $= \frac{mass}{molarmass}= \frac{285.3}{301.1}=0.9475$ mole