7.36 x 1024 free oxygen atoms
Solution.
"N=7.36\\sdot 10^{24};"
"N_A=6.02\\sdot 10^{23}mol^{-1};"
"\\nu=\\dfrac{N}{N_A};"
"\\nu=\\dfrac{7.36\\sdot10^{24}}{6.02\\sdot 10^{23}}=12.2 mol;"
Answer: "\\nu=12.2 mol."
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