What volume in litres does 350.5g of methane (CH4) gas occupy at STP.
Solution:
The molar mass of methane (CH4) is 16 g/mol
Therefore,
Moles of CH4 = (350.5 g CH4) × (1 mol CH4 / 16 g CH4) = 21.906 mol CH4
At STP, one mole of any gas occupies a volume of 22.4 L.
Thus, 21.906 mol of CH4 occupies:
(21.906 mol CH4) × (22.4 L CH4 / 1 mol CH4) = 490.7 L CH4
Answer: 490.7 liters of methane (CH4)
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