Answer to Question #312335 in General Chemistry for Ivan Ackerman

Question

For the chemical reaction

Na2CO3+Ca(NO3)2⟶CaCO3+2NaNO3

how many moles of calcium carbonate (CaCO3) are produced from 6.0 mol of sodium carbonate (Na2CO3)?

Answer 1

The chemical reaction is as follows

$Na_2CO_3 + Ca(NO_3)_2 \longrightarrow CaCO_3+ 2NaNO_3$

1 mole of sodium carbonate react with 1 mole of calcium nitrate to give 1 mole of CaCO₃ and 2 mole of sodium nitrate

so, 6 mole of sodium carbonate will produce 6 mole CaCO₃