Answer to Question #312334 in General Chemistry for Ivan Ackerman

Question

Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia.

N2(g)+3H2(g)⟶2NH3(g)

Assume 0.190 mol N2 and 0.599 mol H2 are present initially.

After complete reaction, how many moles of ammonia are produced?

How many moles of H2 remain?

How many moles of N2 remain?

What is the limiting reactant?

Answer 1

Moles of ammonia produced=?

Mole ratio= 1:2

(2/3)× 0.19= 0.127mole

moles of H2 remain=?

0.599-0.19= 0.409moles

Nitrogen is the limiting reagent