Answer to Question #312331 in General Chemistry for Ivan Ackerman

Question

Consider the reaction shown.

4HCl(g)+O2(g)⟶2Cl2(g)+2H2O(g)

Calculate the number of grams of Cl2 formed when 0.225 mol HCl reacts with an excess of O2 .

Answer 1

n(HCl) = 0.225 mol

m(Cl₂) - ?

Solution:

n(Cl₂) = n(HCl)/2 = 0.225 mol/2 = 0.113 mol

m(Cl₂) = n(Cl₂)*M(Cl₂) = 0.113mol*71g/mol

= 8.02 g

Answer: mass of Cl2 8.02 g