Phosphorus reacts with oxygen to form diphosphorus pentoxide, P2O5 .
4P(s)+5O2(g)⟶2P2O5(s)
How many grams of P2O5 are formed when 2.17 g of phosphorus reacts with excess oxygen? Show the unit analysis used for the calculation by placing the correct components into the unit-factor slots.
Moles of phosphorus are
Moles= 2.17/31= 0.07moles
Moles P2O5 are
(1/3)× 0.07 = 0.023moles
Mass= 284× 0.023
Mass= 6.532g
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