If 2.98 mol of C5H12 reacts with excess O2, how many moles of
CO2 will be produced by the following combustion reaction?
C5H12+8O2⟶6H2O+5CO2
C5H12 + 8O2 ⟶ 6H2O + 5CO2
According to the equation, the moles of CO2 formed is 5 times greater than the moles of C5H12 given:
5*2.98 = 14.9 mol
Comments
Leave a comment