For the chemical reaction
Na2CO3+Ca(NO3)2⟶CaCO3+2NaNO3
how many moles of calcium carbonate (CaCO3) are produced from 6.0 mol of sodium carbonate (Na2CO3)?
Solution:
Balanced chemical equation:
Na2CO3 + Ca(NO3)2 ⟶ CaCO3 + 2NaNO3
According to stoichiometry:
1 mol of Na2CO3 gives 1 mol of CaCO3
Thus,
6 mol of Na2CO3 gives 6 mol of CaCO3
Answer: 6 moles of calcium carbonate (CaCO3) are produced
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