Question #312136

On complete combustion, 0.246 g of an organic compound gave 0.198 g of CO2 and 0.1014 g of H2O. What is the ratio of carbon and hydrogen atoms in the compound?

1
Expert's answer
2022-03-16T14:28:03-0400

All of the carbon from the hydrocarbon is converted to carbon dioxide:


n(C)=n(CO2)=massmolar mass=0.198 g12+216 g/mol=0.0045 moln(C)=n(CO_2 )=\dfrac{mass}{molar\ mass}=\dfrac{0.198\ g}{12+2*16\ g/mol}=0.0045\ mol


All of the hydrogen from the hydrocarbon is converted to water (each water molecule contains two hydrogen atoms):


n(H)=2n(H2O)=2massmolar mass=20.1014 g21+16 g/mol=0.0113 moln(H)=2*n(H_2O )=2*\dfrac{mass}{molar\ mass}=2*\dfrac{0.1014\ g}{2*1+16\ g/mol}=0.0113\ mol


Carbon and hydrogen ratio:


H:C=0.0113:0.0045=2.5:1=5:2H:C=0.0113:0.0045=2.5:1=5:2


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