Answer to Question #311860 in General Chemistry for thel

Question

If 0.590% solution of Na₂CO3 will be used to precipitate Ca⁺² from solution, determine the amount of solution, in grams needed to percipitate 5.00x10²mL of 0.01120M Ca⁺²

Answer 1

V(Ca²⁺) = 500.0 mL = 0.5 L;

C(Ca²⁺) = 0.01120 M;

n(Ca²⁺) = C(Ca²⁺) * V(Ca²⁺) = 0.01120 * 0.5 = 0.0056 moles;

Na₂CO₃ + Ca²⁺ = CaCO₃ + 2Na⁺;

For the chemical reaction:

n(Na₂CO₃) = n(Ca²⁺) = 0.0056 moles;

X(Na₂CO₃) = 0.590%

M(Na₂CO₃) = 106 g/mole;

m(Na₂CO₃) = n(Na₂CO₃) * M(Na₂CO₃) = 0.0056 * 106 = 0.5936 g;

m(solution) = m(Na₂CO₃) * 100%/X(Na₂CO₃) = 0.5936 * 100/0.590 = 100.6 g.

Answer: 100.6 g.