Question

What is the molality of a solution formed from 29.1 g of C7H8 (toluene) dissolved in a 832 g of benzene (C6H6)?

Answer 1

Mass of toluene = 29.1 g , mass of solvent = 832 g

Molar mass of $C_7H_8$ = 84+ 8= 92 $\frac{g}{mol}$

Molality = $\frac{29.1 \times 1000}{92 \times 832}= 0.38$ m