Question

Determine the Weight f the Sample, if

it Used 24.9ml of 0.1Normal Sodium

Hydroxide of Titrant {33.29% of

Busulfan (C7H6O2)} with solution

Answer 1

Volume of solution = 24.9 mL, Normality of solution = 0.1 N, Molar mass of Bisulphan = C₇H₆O₂ = 84+6+32 = 122 g/mole

Mole of NaOH = 0.0025 mole

Mole of Busulphan = 0.0025

Mass of Busulphan = 0.0025 $\times122= 0.305$

Mass of titration = 14 2 g