Answer to Question #311261 in General Chemistry for sessmay_24

Question

Determine the Weight f the Sample, if it Used 24.9ml of 0.1Normal Sodium Hydroxide of Titrant {33.29% of Busulfan (C7H6O2)} 

Answer 1

C₇H₆O₂ is not the Busulfan. This is the benzoic acid.

M(C₇H₆O₂) = 122 g/mole;

NaOH + C₇H₆O₂ = C₇H₅O₂Na + H₂O;

n(NaOH) = C(NaOH) * V(NaOH) = 0.1 * 0.0249 = 0.00249 moles;

n(C₇H₆O₂) = n(NaOH) = 0.00249 moles;

m(C₇H₆O₂) = n(C₇H₆O₂) * M(C₇H₆O₂) = 0.00249 * 122 = 0,3 g;

m(sample) = m(C₇H₆O₂) * 100 %/X(C₇H₆O₂) = 0.3 * 100%/33.29% = 0.9 g.

Answer: 0.9 g.