2. Calculate the AH for the reaction:
CS2 (1) + 2 O2 (g) CO2 (g) + 2 SO2 (g)
Given:
AHCO2 (g) = -393.5 kJ/
mol;
AHSO2 = -296.8 kJ/mol;
AHCS2 (1) = 87.9kJ/mol
The given reaction is CS2(l)+2O2(g)⟶CO2(g)+2SO2(g)CS_2(l)+ 2O_2(g) \longrightarrow CO_2(g)+2SO_2(g)CS2(l)+2O2(g)⟶CO2(g)+2SO2(g)
ΔHf(CO2)=−393.5kJmol\Delta H_f (CO_2)=-393.5 \frac{kJ}{mol}ΔHf(CO2)=−393.5molkJ
ΔHf(SO2)=−296.8kJ/mol\Delta H_f(SO_2)=-296.8 kJ/molΔHf(SO2)=−296.8kJ/mol
ΔHf(CS2)=87.9kJ/mol\Delta H_f( CS_2)=87.9 kJ/molΔHf(CS2)=87.9kJ/mol
ΔHr=ΔHf(CO2)+ΔHf(SO2)−ΔHf(CS2)\Delta H_r= \Delta H_f(CO_2)+\Delta H_f(SO_2)-\Delta H_f(CS_2)ΔHr=ΔHf(CO2)+ΔHf(SO2)−ΔHf(CS2)
ΔHr=−393.5−296.8−87.9\Delta H_r= -393.5-296.8-87.9ΔHr=−393.5−296.8−87.9
ΔHr=−778.2kJmol\Delta H_r= -778.2 \frac{kJ}{mol}ΔHr=−778.2molkJ
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