Anhydrous copper(II) sulfate is difficult to dry completely. What mass of copper(II) sulfate would remain after removing 90% of the water from 250. g of CuSO4×5H2O?
Molar mass=249•7
Molar mass of water in salt= 90
Mass of water in the salt= 90/249.7= 90.1g
(90/100)×90.1= 81.09= mass removed
Remaining mass= 250_-81.09= 168.9g
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