What is the concentration of the original solution if 450 mL, a certain solution is diluted in 750 mL water to form 2.0 L of 1.50 M HCl?
n(HCl) = C(HCl) * V(solution) = 1.50 * 2.0 = 3.0 moles;
C0(HCl) = n(HCl)/V0(solution) = 3/0.45 = 6,67 М.
Answer: 6.67 M.
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