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Answer to Question #310123 in General Chemistry for Lubna
Question #310123
If I have 21 liters of gas held at a pressure of 78 atm and a temperature of 900 K, what will be the volume of the gas if I decrease the pressure to 45 psi and decrease the temperature to 750 K?
Expert's answer
"P1V1T2= P2V2T1"
78× 21×750= 3.06× V2× 900
V2= 1228500/2754
V2= 446L
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