what is volume of a 0.62 mol sample of gas at 10.6 and a pressure of 1.05
Solution.
n=0.62mol;n=0.62 mol;n=0.62mol;
T=10.6oC=283.6K;T=10.6^oC=283.6K;T=10.6oC=283.6K;
P=1.05atm;P=1.05 atm;P=1.05atm;
V−?;V-?;V−?;
PV=nRT ⟹ V=nRTP;PV=nRT\implies V=\dfrac{nRT}{P};PV=nRT⟹V=PnRT;
V=0.62mol⋅0.0821L/atm/mol/K⋅283.6K1.05atm=13.75L;V=\dfrac{0.62 mol\sdot 0.0821 L/atm/mol/K\sdot 283.6K}{1.05 atm}=13.75L;V=1.05atm0.62mol⋅0.0821L/atm/mol/K⋅283.6K=13.75L;
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