calculate the volume that will be occupied by 20.0g carbon dioxide at 25 degree celcius and 1.25 atm.
Mass of carbon dioxide = 20.0 g ,
Mole of carbon dioxide = "\\frac{20}{44}" = 0.45
pressure = 1.25 atm , temp = 25 oC = 298 K
PV=nRT
1.25×V= 0.45×0.0821×298
V= 0.11 L
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