Question #309747

How many grams of FeCl3 are present in 15.00 mL of the solution? (Molar mass of FeCl3 = 162.2 g/mol)


1
Expert's answer
2022-03-12T01:58:04-0500

Solution:

V=15.00mL=15.00103L;V=15.00mL=15.00\sdot10^{-3}L;

M(FeCl3)=162.2g/mol;M(FeCl_3)=162.2 g/mol;

ν=VVM;\nu=\dfrac{V}{V_{M}};

ν=15.0010322.4=0.67103mol;\nu=\dfrac{15.00\sdot10^{-3}}{22.4}=0.67\sdot 10^{-3}mol;

ν=mM(FeCl3)    m=νM(FeCl3);\nu=\dfrac{m}{M(FeCl_3)}\implies m=\nu\sdot M(FeCl_3);

m=0.67103mol162.2g/mol=108.67103g=0.109g;m=0.67\sdot10^{-3}mol\sdot162.2g/mol=108.67\sdot 10^{-3}g=0.109g;

Answer: m=0.109g.m=0.109g.



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