Answer to Question #309747 in General Chemistry for kirby

Question

How many grams of FeCl₃ are present in 15.00 mL of the solution? (Molar mass of FeCl₃ = 162.2 g/mol)

Answer 1

Solution:

$V=15.00mL=15.00\sdot10^{-3}L;$

$M(FeCl_3)=162.2 g/mol;$

$\nu=\dfrac{V}{V_{M}};$

$\nu=\dfrac{15.00\sdot10^{-3}}{22.4}=0.67\sdot 10^{-3}mol;$

$\nu=\dfrac{m}{M(FeCl_3)}\implies m=\nu\sdot M(FeCl_3);$

$m=0.67\sdot10^{-3}mol\sdot162.2g/mol=108.67\sdot 10^{-3}g=0.109g;$

Answer: $m=0.109g.$