Answer to Question #309502 in General Chemistry for Love

Question

A certain mas of hydrogen gas collected over water at 6°c and 765mmHg pressure has a volume of 35cm^3, calculate the volume when its dry at STP (S.V.P of water 6°c =7mmHg)

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Answer 1

P_total=P_H2 + P_H2O

765= P_H2O +7

P_H2O = 758

P₁V_1÷T₁ = P₂V₂÷T₂

T₁= 6+273= 279K

P₁= 758mmHg

V₁= 35cm³

T₂= 273K

P₂= 760mmHg

V₂=?

758×35÷279= 760×V₂ ÷273

V₂=(758×35×273)÷(279×760)

=34.16cm³