Answer to Question #309499 in General Chemistry for whitney

Question

Gaseous butane  (CH3(CH2)2(CH3)

 will react with gaseous oxygen (O2)

 to produce gaseous carbon dioxide (CO2)

 and gaseous water (H2O). Suppose 4.6 g of butane is mixed with 33.3 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to 2 significant digits.

Answer 1

Moles of butane=4.6g×1/58

=0.0793 moles C₄H₁₀

Moles of oxygen= 33.3×1/32

=1.041 moles of O₂

Therefore,, maximum mass of CO₂=1.041×16/25×22

=0.015 g to two significant digits

=0.02g