Question

Determine the boiling point of a solution of 10 grams of a substance of molecular weight 94 g/mol in 500 grams water.

Answer 1

Mass of water =500 g

Mass of solute = 10

$\Delta T_b =K_bm$

$\Delta T_b= 0.512× \frac{10×1000}{500]}$

$\Delta T_b = 10.2 K$

Elevation in boiling piint is 10.2 K