Answer to Question #309308 in General Chemistry for Rachael Khan

General Chemistry

Question #309308

What is the total number of moles of atoms present in 1 mole of (SO4)3 (PO4)2?

Expert's answer

n((SO₄)₃ (PO₄)₂) = 1 mol;

So, n(S) = 3 moles; n(O) = 12 + 8 = 20 moles; n (P) = 2 moles.

Answer: n(S) = 3 moles, n(O) = 20 moles; n(P) = 2 moles,

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