Answer to Question #309179 in General Chemistry for yow

Question

How many grams of Ag₂ CrO4 will precipitate when 86ml of 0.2 molar Ag₂Cro, is added to 500ml of 6.3 molar K₂ CrO4? Molar mass of Ag₂ CrO4 = 331.74 g/mol

Balanced Equation: 2AgNO3 + K₂CrO4 Ag₂ CrO4 + 2KNO3

Answer 1

Moles of AgNO₃ = 0.2×86÷1000=0.0172

Moles of K₂CrO₄=6.3×500÷1000= 3.15

Limiting reagent is AgNO₃

Moles of Ag₂CrO₄ formed = 0.0172÷2= 0.0086

Mass of Ag₂CrO₄ produces = 0.0086×331.74 = 2.85296g