Question #308980

What is the pH solution containing 0.30 M HCOOH and 0.52 M HCOOK?Compare your result with the pH of a 0.30 M HCOOH solution


1
Expert's answer
2022-03-10T10:47:43-0500

HCOOH(aq) + H2O(l) = H3O+(aq) + HCOO-(aq)

pKa = 3.77

pH=pKa+log([HCOO][HCOOH])pH = pKa + log ( \frac{[HCOO^-]}{[HCOOH]} )

pH=3.77+log([0.52][0.30])pH = 3.77 + log ( \frac{[0.52]}{[0.30]} )

pH = 4.01


Ka=[HCOO][H+][HCOOH]=x20.3Ka=\frac{[HCOO^-][H^+]}{[HCOOH]}=\frac{x^2}{0.3}

pKa=logx2log0.3pKa=logx^2-log0.3

logx2=0.52+3.77=4.26logx^2=0.52+3.77=4.26

logx=pH=4.26/2=2.13


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