Question

I have a balloon that can hold 100 liters of air.if I blow up this balloon with 3 moles of oxygen gas at a pressure of 1 atmosphere, what is the temperature of the ballon

Answer 1

According to the ideal gas law,

$T=\frac{PV}{nR}=\frac{1\ atm\times100\ L}{3\ mol\times0.08206\frac{L\cdot{atm}}{mol\cdot{K}}}=406\ K=406-273=133\degree{C}$

Answer: 133^oC