What is the molarity of a sodium hydroxide solution if 4.50 mL of the solution is titrated to the end
point, with 5.00 mL of acetic acid with 0.0830M?
NaOH + HAc = NaAc + H2O;
C1 * V1 = C2 * V2;
C(NaOH) * V(NaOH) = C(HAc) * V(HAc);
C(NaOH) = C(HAc) * V(HAc) / V(NaOH) = 0.0830 * 5 / 4.5 = 0.0922 M.
Answer: 0.0922 M.
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