Answer to Question #308520 in General Chemistry for My name

Question

Calculate the molality of a solution that contains 27.5 g of barium chloride (BaCl2) in 100 mL of water.

Answer 1

100 ml ×1.00g/1 ml=100 g

Molar mass of BaCl₂=208.23 g/mol

27.5 g×1 mol BaCl₂/208.23g/mol

=0.13203 moles BaCl₂

10³g×0.132034 moles BaCl₂/100g water

= 1.3203 moles BaCl_2.

_{Thus molality is equal to:}

=1.32 mol kg^-1

Therefore,, the answer is;

1.32mol kg^-1