A saline solution is prepared by dissolving 5.04 g of NaCl in 95.0 g of water.
Calculate the following:
a. Mole fraction of the solute and the solvent
b. % mass of the solute
c. Concentration of solution in ppm
Please put what letter did you answer in every solution
Solution:
solute = NaCl
solvent = H2O
The molar mass of NaCl is 58.44 g/mol
The molar mass of water (H2O) is 18.015 g/mol
Calculate the moles of each component:
Moles of NaCl = (5.04 g NaCl) × (1 mol NaCl / 58.44 g NaCl) = 0.0862 mol NaCl
Moles of H2O = (95.0 g H2O) × (1 mol H2O / 18.015 g H2O) = 5.2734 mol H2O
Therefore,
Total moles of solution = Moles of NaCl + Moles of H2O = 0.0862 mol + 5.2734 mol = 5.3596 mol
Calculate the mole fraction (χ) of each component:
χ = Moles of component / Total moles of solution
Therefore,
χsolute = χNaCl = Moles of NaCl / Total moles of solution = (0.0862 mol) / (5.3596 mol) = 0.016
χsolute = 0.016
χsolvent = χH2O = Moles of H2O / Total moles of solution = (5.2734 mol) / (5.3596 mol) = 0.984
χsolvent = 0.984
Calculate the %mass of each component:
Percent by mass = (Mass of component / Mass of solution) × 100%
Mass of solution = Mass of NaCl + Mass of H2O = 5.04 g + 95.0 g = 100.04 g
Therefore,
%mass of solute = %mass of NaCl = (5.04 g / 100.04g) × 100% = 5.04%
%mass of solute = 5.04%
%mass of solvent = %mass of H2O = (95.0 g / 100.04g) × 100% = 94.96%
%mass of solvent = 94.96%
Calculate the concentration of solution in ppm:
ppm = parts per million = (grams of solute / grams of solution) × 1000000
Therefore,
Concentration of solution = (Mass of NaCl / Mass of solution) × 1000000
Concentration of solution = (5.04 g / 100.04g) × 1000000 = 50379.85 ppm = 50380 ppm
Concentration of solution = 50380 ppm
Answers:
a)
The mole fraction of the solute (χsolute) is 0.016
The mole fraction of the solvent (χsolvent) is 0.984
b)
The percent by mass of the solute (%mass of solute) is 5.04%
c)
The concentration of solution is 50380 ppm
Comments
Leave a comment