Percent Composition and Empirical Formula
1. The chemical analysis of aspirin indicates that the molecule is 60.00% carbon, 4.44% hydrogen,
and 35.56% oxygen. Determine the empirical formula for aspirin.
2. **Glucose is a simple sugar produced during photosynthesis. It has a molecular formula of C6H12O6.
a. Compute for the percent composition.
b. Determine the empirical formula.
1 Empirical formula
C. H. O
Moles. 60÷12. 4.44÷1 35.56÷16
= 5. 4.44. 2.2225
Mole ratio=5÷2.2225:4.44÷2.225:2.225÷2.225
=2.25:2:1
=9:8:4
The empirical formula is C9H8O4
2(a) Percentage composition of C6H12O6
Carbon = (12×6÷180)×100=40%
Hydrogen= (12×1÷180)×100= 6.66%
Oxygen=(16×6÷180)×100 = 53.33%
(b) C:H:O = 6:12:6
Simplest ratio =1:2:1
Empirical formula is CH2O
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