Answer to Question #308297 in General Chemistry for kode

Question

When copper is heated with an excess of sulfur, copper(I) sulfide is formed. In a given experiment, 1.50 g of copper was heated with excess sulfur to yield 1.53 g copper(I) sulfide. What is the percent yield?

Answer 1

The equation for the reaction is

2Cu_(s) +S_(s) $\to$ Cu₂S_(s)

Moles of Cu= 1.5÷63.5 = 0.02362

Expected moles of Cu₂S=0.02362÷2

=0.01181

Moles of Cu₂S oobtained=1.53÷159

=0.009623

Percentage of yield =(0.009623÷0.01181) ×100 =81.48%