Answer to Question #308013 in General Chemistry for Argeena

Question

The solubility of silver chloride AgCl is 1.2×10^-10 at 298 Kelvin. Calculate the solubility of silver chloride AgCl.

( Using k_sp= s²)

Answer 1

Solution:

AgCl(s) ⇌ Ag⁺(aq) + Cl^–(aq)

__S________S________S____

Thus,

S = S(AgCl) = [Ag⁺] = [Cl^–]

The K_sp expression for AgCl(s) is:

K_sp = [Ag⁺] × [Cl^–]

Therefore,

K_sp = [S] × [S]

1.2×10^–10 = S²

S = (1.2×10^–10)^1/2 = 1.095×10^–5

S(AgCl) = S = 1.095×10^–5 M = 1.1×10^–5 M

S(AgCl) = 1.1×10^–5 M

Answer: The solubility of silver chloride (AgCl) is 1.1×10^–5 M