Question

How much 0.17 HCI is required to make 250 ml of solution with a pH of 1.79.

Answer 1

[H⁺] = 10^-pH = 10^-1.79 = 0.01622 M

n(H⁺) = n(HCl) = 0.01622 mol/l × 0.250 l = 0.004055 mol

V(solution) = n(HCl)/M(HCl) = 0.004055 mol / 0.17 mol/l = 0.02385 l = 23.85 ml