How much 0.17 HCI is required to make 250 ml of solution with a pH of 1.79.
[H+] = 10-pH = 10-1.79 = 0.01622 M
n(H+) = n(HCl) = 0.01622 mol/l × 0.250 l = 0.004055 mol
V(solution) = n(HCl)/M(HCl) = 0.004055 mol / 0.17 mol/l = 0.02385 l = 23.85 ml
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment