What is the temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr if it occupies 13.3 L at 55°C and 744 torr?
The pressure is constant, so we can use Charles’ Law:
V1/T1 = V2/T2
Invert both sides of the equation:
T1/V1 = T2/V2
Multiply both sides by V2:
T2 = T1 x V2/V1
V1 = 13.3 L; T1 = (55 + 273.15) K = 328.15 K
V2 = 11.2 L; T2 = ?
T2 = 328.15 K x 11.2 L/13.3 L = 276 K = 3°C
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