Question #307646

an unknown substance with a mass of 100 grams absorbs 1000 J while undergoing a temperature increase of 15 C. What is the specific heat of the substance 


1
Expert's answer
2022-03-08T22:00:04-0500

Q=m×c×dTQ= m×c ×dT

1000= 0.1×c× 15

C= 1000/1.5

C= 666.67J/kg/°c


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