Answer to Question #307549 in General Chemistry for nonhle

Question

When a research balloon is released at sea level, where the temperature is 14.8°C

14.8°C and the atmospheric pressure is 1.01×10

5

 Pa

1.01×105 Pa, the helium in it has a volume of 12.9 m

3

12.9 m3. The balloon reaches an altitude of 32 km

32 km, where the temperature is −44.1°C

−44.1°C and the pressure is 867 Pa

867 Pa. What is the volume of the helium at this altitude? 

Answer 1

T₁=14.8+273= 287.8K

P₁=1.01×10⁵ Pa

V₁=12.9 m³

T₂=-44.1+273= 228.9K

P₂=867Pa

V₂=?

P₁V₁÷T₁ = P₂V₂÷T₂

1.01×10⁵×12.9÷287.8 = 867×V₂÷228.9

V₂= 1.01×10⁵×12.9×228.9÷(287.8×867)

=1195.22m³