Answer to Question #307454 in General Chemistry for Dada

Question

If 3.0 mol PbO2 reacts with excess SO2, 2 mol PbSO4 is produced. What is the percentage yield?

Answer 1

The equation for the reaction is

PbO_2(s) + SO_2(g) $\to$ PbSO_4(s)

One mole of PbO₂ is expected to give one mole of PbSO_4.

Therefore, expected moles were 3.

Percentage yield= (2÷3) ×100

=66.67%