Question #307454

If 3.0 mol PbO2 reacts with excess SO2, 2 mol PbSO4 is produced. What is the percentage yield?

Expert's answer

The equation for the reaction is

PbO2(s) + SO2(g) →\to PbSO4(s)

One mole of PbO2 is expected to give one mole of PbSO4.

Therefore, expected moles were 3.

Percentage yield= (2÷3) ×100

=66.67%


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