Calculate the pH of an acetic acid solution at 3.20 x 10-4 mol/L (% ionization = 1.30%).
[H3O+] = 3.20×10-4 ×(1.3 ÷100)
=4.16×10-6
pH= -log 4.16×10-6
=5.38
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment