Question #307205
Calculate the pH of an acetic acid solution at 3.20 x 10-4 mol/L (% ionization = 1.30%).
Expert's answer
[H3O+] = 3.20×10-4 ×(1.3 ÷100)
=4.16×10-6
pH= -log 4.16×10-6
=5.38
Calculate the pH of an acetic acid solution at 3.20 x 10-4 mol/L (% ionization = 1.30%).
[H3O+] = 3.20×10-4 ×(1.3 ÷100)
=4.16×10-6
pH= -log 4.16×10-6
=5.38
