Answer to Question #306856 in General Chemistry for Jester

Question

How much ethanol is produced from the starting material of 987.1 Grams of glucose?

Answer 1

The equation for fermentation of ethanol is

C₆H₁₂O_6(aq)$\to$ 2C₂H₅OH_(aq) + 2CO_2(g)

Molar mass of glucose= 180

Molar mass of ethanol = 46

One mole of glucose gives 2 moles of ethanol.

Therefore, 180g of glucose yields 92g of ethanol.

Mass of ethanol produced=(987.1÷180) × 92 = 504.52g