Answer to Question #306253 in General Chemistry for Heinz

Question

For the following reaction, 5.59 grams of oxygen gas are mixed with excess carbon (graphite). The reaction yields 7.10 grams of carbon dioxide.

carbon (graphite) ( s ) + oxygen ( g )  carbon dioxide ( g )

What is the theoretical yield of carbon dioxide? ____ grams

What is the percent yield for this reaction? ____ %

Answer 1

To determine theoretical yield of $CO_2$ ,we need to calculate number of moles of $O_2$

$C_s+O_2\to CO_2$

$\frac{5.59of O_2}{32.0 g/molO_2}=0.175moles of O_2$

$0.175moles of O_2\times\frac{1moleO_2}{1moleCO_2}×44.01g/molof CO_2=7.70175$

$7.70175gof CO_2$ is the theoritical yield of $CO_2$

2.The percent yield of $CO_2$ is:

Actual yield of CO2 divided by theoretical yield of CO2 ×100%

$=\frac{7.10g}{7.70175}×100\%=92.187\%$