Answer to Question #306252 in General Chemistry for MYCA

Question

 In a biochemical assay, a chemist needs to add 2.93 g of glucose to a reaction mixture. Calculate the volume in mL of a 1.35M glucose solution she should use for the addition.

Answer 1

Solution:

Moles = Mass / Molar mass

The molar mass of glucose is 180.156 g/mol

Therefore,

Moles of glucose = (2.93 g) / (180.156 g/mol) = 0.01626 mol

Molarity = Moles / Volume

Volume = Moles / Molarity

Therefore,

Volume of glucose solution = (0.01626 mol) / (1.35 M) = 0.012 L = 12 mL

Answer: 12 mL of glucose solution should be used