Answer to Question #306222 in General Chemistry for Ali

Question

2. A student experimentally measured the density of gold as 19.74g/cm3. A handbook reports a value of 19.02 g/cm3. Calculate the percent error in the student’s measurement.

Answer 1

$\%\; error=\; ((original-\; measured)/original))\times \; 100$ %error= ((original- measured)/original)× 100

= (0.72/19.02)× 100

= 3.79%