How many liters of a stock solution of 2.50M KNO3 are needed to prepare 10 L of 0.78M KNO3?
M1V1=M2V2
We have M1 = 2.5M
M2 = 0.7M
V2 = 10L
We need to find V1 = M2V2/M1
= (0.7M x 10L)/2.5M
= 2.8L
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment