Question #305804
Using the balanced equation above, how many moles ofAl2(SO4)3 would be produced if you began the reaction with 5.8 mol of Al(OH)3?
Expert's answer
From the balanced equation;
5.8 mol Al(OH)3 × 1 mol Al2(SO4)3 / 1 mol Al(OH)3
= 5.8 mol Al2(SO4)3
