Question #305504

Pb(NO3)2 + 2 NaI = PbI2 + 2 NaNO3

How many moles of lead (II) nitrate are needed to react completely with 10 moles of sodium iodide?

Expert's answer

Pb(NO3)2 + 2NaI = PbI2 + 2NaNO3

With chemical reaction n(Pb(NO3)2) = ½ n(NaI), so 10 moles of sodium iodide (NaI) will interact with 5 moles of lead nitrate (Pb(NO3)2).

Answer: 5 moles.



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