Question #305128

What is the volume of a sample of ethane at 467k and 1.1atm ,if it occupies 405ml at 298k and 1.1atm


1
Expert's answer
2022-03-03T13:26:03-0500

According to the combined gas law,


P1V1T1=P2V2T2\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}


Therefore,


V2=P1V1T2T1P2=1.1 atm×405 mL×467 K298 K×1.1 atm=635 mLV_2=\frac{P_1V_1T_2}{T_1P_2}=\frac{1.1\ atm\times405\ mL\times467\ K}{298\ K\times1.1\ atm}=635\ mL


Answer: 635 mL


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