What is the volume of a sample of ethane at 467k and 1.1atm ,if it occupies 405ml at 298k and 1.1atm
According to the combined gas law,
"\\frac{P_1V_1}{T_1}=\\frac{P_2V_2}{T_2}"
Therefore,
"V_2=\\frac{P_1V_1T_2}{T_1P_2}=\\frac{1.1\\ atm\\times405\\ mL\\times467\\ K}{298\\ K\\times1.1\\ atm}=635\\ mL"
Answer: 635 mL
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