Calculate the Molarity of each of the following solutions:
a. 185 g of sucrose, C12H22011 in 1.00 L of solution
b. 6.30 g of HNO3 dissolved in 255 ml of solution.
a) moles= mass/ rmm= 185/342= 0.54 moles
Molarity = moles/ litre
= 0.54/1= 0.54M
b)moles= 6.3/63= 0.1 moles
Molarity = 0.1/0.255= 0.39M
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