given the equation: CH4 + 2O2 > CO2 + 2H2O How how many grams of CH4 I needed to react with 3.2 grams of O2?
Molar mass of CH4=16g/mol_4=16g/mol4=16g/mol
Molar mass of Oxygen=32g/m=32g/m=32g/m
Moles of O2=3.232=0.1_2=\frac{3.2}{32}=0.12=323.2=0.1 moles
Moles of CH4=12×0.1=0.05_4=\frac{1}{2}×0.1=0.054=21×0.1=0.05 moles
Grams of CH4=0.05×16_4=0.05×164=0.05×16
=0.8g=0.8g=0.8g
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments